Solució: \begin{align} ∑ F_(verticals) = ma = 0 &= \cssId{Step1}{T_C + T_D} \\[3px] &\cssId{Step2}{∑M(G) = T_C · d - T_D · d} \\[3px] &\cssId{Step3}{TC = TD = (𝑚𝑔)/2} \\[3px] \end{align}